A street with two lanes, each 10 ft wide, goes through a semicircular tunnel with a radius of 12 ft....

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Tanong

A street with two
lanes, each 10 ft
wide, goes through a semicircular tunnel
with a radius of 12 ft.
How high is the

tunnel at the edge of
each lane? Round off
to 2 decimal places.​

Mga sagot sa #1 sa Tanong: A street with two
lanes, each 10 ft
wide, goes through a semicircular tunnel
with a radius of 12 ft.
How high is the

tunnel at the edge of
each lane? Round off
to 2 decimal places.​

Problem:

A street with two lanes, each 10 ft wide, goes through a semicircular tunnel with a radius of 12 ft. How high is the tunnel at the edge of each lane? Round off to 2 decimal places.

1.) What conic section is referred?

Answer:

It is referred to circle.

2.) What is the formula to be used?

Answer:

The equation of the circle is x² + y² = a²

3.) What are the given?

Answer:

The given are:

x = The street is 10 ft wide (width)

a = The semicircular tunnel has a radius of 12 feet (the slant length)

4.) What is the coordinate of pt P?

Answer:

The coordinate of pt P is (150, 100)

5.) How high refers to ordinate or abscissa?

Answer:

The “how high” refers to the coordinate-y or the ordinate.

6.) How high is the tunnel at the edge of each lane? Round off to 2 decimal places.

Solution:

Using the equation of the circle to get the height of the tunnel

a² = x² + y²

12² = 10² + y²

y² = 12² – 10²

y² = 144 – 100

[tex]y = sqrt{44}[/tex]

y = 6.63 ft

Answer:

The height of the tunnel at the edge of each lane is y = 6.63 ft.

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